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4.905x^2-57x-220=0
a = 4.905; b = -57; c = -220;
Δ = b2-4ac
Δ = -572-4·4.905·(-220)
Δ = 7565.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{7565.4}}{2*4.905}=\frac{57-\sqrt{7565.4}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{7565.4}}{2*4.905}=\frac{57+\sqrt{7565.4}}{9.81} $
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